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Delhi University MCA Previous Year Questions (PYQs)
Delhi University MCA Time And Work PYQ
X works twice as fast as Y . Y alone can finish the work in nine days . X and Y together can finish the work in _____ days.
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Solution
Persons A, B, and C can finish a work in 15, 10, and 12 days respectively. Person B and person C start the work together but are asked to leave after 4 days. In how many days will the remaining work be done by person A?
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Solution
A-------15B-------10
C-------12
Total work (LCM of A,B,C) = 60
Work done by B and C in a day = (6+5)=11
B and C word done in 4 days = 44
Remaining work for A=16
A completes 4 work in a day, so A take 4 more days to complete 16 works.
A
and B can complete a work in 15 days. B and C can complete the same work in 20
days. If A, B and C together can finish it in 10 days, then A and C can
complete the same work in____days.
Go to Discussion
Solution
One Day work of A+B = 1/15One Day work of B+C = 1/20
Lwt One Day work of A+C = 1/x
One Day work of A+B+C = 1/10
2.One Day work of A+B+C =(One Day work of A+B)+(One Day work of B+C)+(One Day work of A+C)
210=115+110+1x
x=12
A+C can complete the same work in 12 days.
Delhi University MCA
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and More.
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